12-118. ů = (0.05s) m/s² v = 4 m/s 50 m The truck travels in a circular path having a radius of 50 m at a speed of v = 4

m/s. For a short distance from s = 0, its speed is increased by = (0.05s) m/s², where s is in meters. Determine its speed and the magnitude of its acceleration when it has moved s = 10 m. Note, in the Hibbeler textbook, a dot above anything indicates the time rate of change. Thus, Ans: atm = (0.5, 0.42) m/s², thus v = 4.58 m/s and a = 0.653 m/s² = dv dt