Search for question
Question

2. Construct binomial probability distributions for p = 0.290 and P(x) = ncxp*q"-x a. n=3. = n! (n-x)!x!' P(0)=3(0.29) (0.71) 3-0 = 3! (0.29)°(0.71)³ = 0.3579 (3-0)!0! b. n = 4. 4! P(0)=4(0.29)° (0.71)4-0 = (0.29)°(0.71) = 0.2541 (4-0)!0! c. n = 5. 5! P(0)=C(0.29)°(0.71) 5-0 = (0.29)°(0.71) 5 = 0.1804 (5-0)!0! (The results are summarized in the tables below.) Insert Table from Excel Spreadsheet n=3 Insert Table from Excel Spreadsheet n=4 Insert Table from Excel Spreadsheet n=5

Fig: 1