2) Given are the two vector functions Calculate the derivative \vec{u}(t)=(1+t) \vec{\imath}+4 \vec{\jmath}+2 t^{3} \vec{k} \quad \text { and } \quad \vec{v}(t)=2 t^{2} \vec{\imath}+t \vec{\jmath}+2 \vec{k} \left[\frac{d}{d t}[\vec{u}(t) \times \vec{v}(t)]\right]_{t=1}