Question
A four-sided closed field traverse has the following angles: A = 81°53'30"; B = 70°28′30"; C = 86°09′30"; D =121*30'30". The lengths of the sides are as follows: AB = 636.45 ft; BC = 654.45 ft; CD= 382.65 ft; DA= 469.38 ft. The bearing of AB is S 17°17' W. BC is in the N.E. quadrant. Draw the four-sided closed traverse