Cold-air flow speed 15 m s−1 changes to 10 m s-1 after passing a hydraulic jump. This air is 10°C colder than the surroundings. Using the following equation and diagram, Δθυ 1 M2+191 z = constant T Iv บ (M is the wind speed, g is the acceleration owing to gravity, A0, is the virtual potential temperature difference, Tv is absolute virtual air temperature and z is the altitude. The constant is the same along a streamline). how high can the hydraulic- jump jump? Z cold air M₁- 2 1 eamlin Z2 hydraulic stree jump Z₁ 0 Assume Δθη = AT and g = T 0.0333ms 2K-1 and z₁ =100m. How high did the hydraulic jump jump (Zɔ-Z₁). s-1 after passing a hydraulic jump. This air is 10°C colder than the surroundings. Using the following equation and diagram, Δθυ 1½ ½ M² M² + g z = constant Tv บ (M is the wind speed, g is the acceleration owing to gravity, A₁, is the virtual potential temperature difference, Tv is absolute virtual air temperature and z is the altitude. The constant is the same along a streamline). how high can the hydraulic- jump jump? N 2 Z2 cold air 1 eamlin hydraulic stre jump M X 0 Assume Δθυ = ΔΤ and اوا Tv - ― 0.0333ms 2K-1 and z₁ =100m. How high did the hydraulic jump jump (Z2-Z1). m.