Consider a layer of water flows between down an inclined fixed plate, as shown in the figure below, the velocity distribution for the fluid flow is given by: \frac{u}{U}=2 \frac{y}{h}-\left(\frac{y}{h}\right)^{2}

where U is the free surface velocity, the density of water is 1000 kg/m, the dynamic-4viscosity of water is 8.90 x 10 Pa-s and h = 0.1 m. Assume a unit plate width. a. The magnitude and direction of shear stress acting on the plate, for U = 2 m/s. (30 points) b. Plot the shear stress variation versus the y direction, for U = 2 m/s. Interpret your result. If the velocity profile is linear between the plate and the free surface: c. Determine the free surface velocity U. d. Plot the shear stress variation versus the y direction, for U = 2 m/s. Compare your result(25 рoints)with part b.