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Determine the enthalpy of reaction,in kJ,for:3A+4B2→A3B8△H=?3A+4B2→A3B8△H=?Given the thermodynamic data for the following reactions:A3B8+5D2→3AD2+4B2D△H=A3B8+5D2-3AD2+4B2DAH--2,113.7kJA+D2→AD2△H=A+D2→AD2△H=-237.5kJB2+D2→B2D△H=B2+12D2→B2D△H=-426.0kJYour answer should be numerical and neglect units (e.g.,if you calculate 3.5kJ theninput 3.5).Make sure your sign is correct!!!

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