Energy Conservation: Homework#1, second semester 2023/2024 Due date: No Later Than Thursday, May 23rd, 1:30 pm Chiller for Hotel: Replacing the old chiller (COP = 1.7) with a New One (COP = α) Chiller COP Old 1.7 Cost initial 0.00 Cost installation O&M Replacing parts Annual Energy Consumption $ 2,830 293,000 *σ 0.00 $ 1360 Every 5 years kWh/Year Needs to be New a $ 19,800* ẞ $2,750 Additional Data :- $ 640 $ 0.00 calculated Find: Price for electricity 0.19 S/kWh, Electric Grid Efficiency = 33% Duration 10 years, interest rate is 9% Old chiller parts replacement is scheduled in years 2 & 7 COP = QL/Win, Cooling energy in both chillers should be the same Emissions produced in 1 kWh of Fuel-Oil#6 in power-station CO2 → 0.263 kg/kWh, NO、⇒ 0.743 g/kWh, SO、 ⇒ 1.47 g/kWh 1. Annual site energy savings (2.0 Grades) 3. Annual cost savings (2.0 Grade) 2. Annual source energy savings (0.75 Grade) 4. NPV & SIR (3.0 Grades) 5. Annual reduction in: CO2, NOx and SOX (2.25 Grades) m . ((1+i)"−1\ - 1/na = 2.38 + 45/100 i(1+i)" \(1+i)"/ 45: the 4th and 5th digits of student's ID# 2.38: constant number B=123/100 = 1.23 123: first three digits of student's ID# σ 1.067/100 67: Last two digits of student's ID# 1.0: constant number Solution Annual site energy savings = kWh/yr Show hand written calculations below/nAnnual source energy savings = Show hand written calculations below Annual cost savings “Present value” = Show hand written calculations below $ Kwh/yr/nNPV = $ Show hand written calculations below Annual reduction in: CO₂ Annual reduction in : NOx Annual reduction in : SOX SIR = Ton Kg Kg

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