Fig.4. Fig.1. Fig. 2 Fig. 3. Q 1/2 Q R π/4 1/2 Rod π/2 A small, electrostatically charged source sphere, Q1, rests on an insulating (glass) pedestal, at a distance of 1/2 from a vertical fiber. Another small, electrostatically charged test sphere, Qo, is attached to a massless, non-conductive horizontal rod of length 1-10 cm. The horizontal rod is supported at its midpoint by a non-conductive fiber (solid circular cross section, diameter D=2 mm, shear modulus G=2.9 GPa, L=15 cm). A third non-charged sphere, Q2 is attached to the horizontal rod to maintain horizontal balance. The repulsive electrostatic force between Q1 and Qo creates torsion in the fiber, which causes rotation of the horizontal rod to an angle e, as indicated on the scale. Separation distance can be calculated from 6. 1. Find the magnitude of the electrostatic force, F10, between Q₁ and Qo if = π/4. Hint: you will need to consider the torsional mechanics of the fiber. × N F= 0.042 2. Assuming that Q1 and Qo are equally charged, use Coulomb's law to calculate the charge magnitude on each sphere for the conditions above. |Q|=|Qol=137e-06 × C 3. Find the magnitude of the electric field, E, at Qo- |E|= 1.24e-05 × N/C

Fig: 1