Question

Find symmetric equations of the line through the point (-1,-2, 2) and parallel to the vector (2, 3, 9). \frac{-x+1}{2}=\frac{-y+2}{3}=\frac{-z-2}{9} \frac{-x-1}{2}=\frac{-y-2}{3}=\frac{-z+2}{9} \frac{x+1}{2}=\frac{y+2}{3}=\frac{z-2}{9} \frac{x-1}{2}=\frac{y-2}{3}=\frac{z+2}{9}

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