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Question 31157

posted 1 years ago

What is the angular speed of a satellite in a geostationary orbit around the Earth? *(1 Point)
1.2 \times 10^{-5} \mathrm{rad} s^{-1}
2.6 \times 10^{-1} \mathrm{rad} s^{-1}
4.2 \times 10^{-3} \mathrm{rad} s^{-1}
7.3 \times 10^{-5} \mathrm{rad} s^{-1}

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Question 31164

posted 1 years ago

Satellites N and F have the same mass and are in circular orbits about the same planet.The orbital radius of F is greater than that of N.
Which is greater for F than for N?
O angular speed
O gravitational force on the satellite
O kinetic energy
orbital period

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Question 31169

posted 1 years ago

An object moves freely at 90° to the direction of a gravitational field.
The acceleration of the object is *
) in the direction of the gravitational field.
zero
opposite to the direction of the gravitational field.
O at 90° to the direction of the gravitational field.

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Question 31153

posted 1 years ago

Passengers on a carnival ride move at constant speed in a horizontal circle of radius 5.0m,making a complete circle in 4.0 seconds. What is their acceleration? *(1 Point)
15 m s^{-2}
8.0 m s^{-2}
12 \mathrm{~ms}^{-2}
1.3 m s^{-2}

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Question 31159

posted 1 years ago

The following are quantities associated with a body performing Simple Harmonic Motion:
1. The body's velocity
2. The accelerating force acting on the body
3. The acceleration of the body.
Which of these quantities areexactly in phase with each other?
1 and 3 only
All of these quantities
O 1 and 2 only
O None of these quantities
O 2 and 3 only

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Question 31160

posted 1 years ago

A 0.1 kg mass hanging from a light helical spring produces an equilibrium extension of 0.1 m.The mass is pulled vertically downwards by a distance of 0.02m and then released. Taking g =10 N/kg, the equation relating displacement x of the mass from its equilibrium position and the time t after release is: *(1 Point)
\frac{x}{m}=0.02 \cos \left[0.1\left(\frac{t}{s}\right)\right]
\frac{x}{m}=0.02 \sin \left[0.2 \pi\left(\frac{t}{s}\right)\right]
\frac{x}{m}=0.1 \sin \left[10\left(\frac{t}{s}\right)\right]
\frac{x}{m}=0.02 \cos \left[10\left(\frac{t}{s}\right)\right]
\frac{x}{m}=0.1 \cos \left[0.2 \pi\left(\frac{t}{s}\right)\right]

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Question 31161

posted 1 years ago

For a simple pendulum undergoing Simple Harmonic Motion with small oscillations, which of the following correctly describes the Kinetic Energy (KE) of the bob and the Tension of the thread supporting the bob at zero displacement (i.e. passing through the equilibrium position)? *
O The KE is zero and the Tension is at a Maximum
O The KE is zero and the Tension is at a Minimum
The KE is at a Maximum and the Tension is at a Maximum
O The KE is at a Maximum and the Tension is at a Minimum
The KE is at a Minimum and the Tension is zero

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Question 31163

posted 1 years ago

An object oscillates with Simple Harmonic Motion as described by the equation shown below,where x represents the displacement in metres and t, the time in seconds, s.
What is the period of the motion in seconds?
x=(1.6 m) \cos (3 \pi t)
\frac{1}{3 \pi}
\frac{3}{2}
3 \pi
\frac{2}{3}

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Question 31154

posted 1 years ago

The diagram represents the gravitational field and potential for a planet-moon system.
Which area in the graph shows the total gravitational field strength, g = 0 *
O None of the regions highlighted has g=0
O D
DA
В

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Question 31152

posted 1 years ago

An object of mass m moves in a circle of radius r. It completes n revolutions every second.What is the kinetic energy of the object?*
\frac{m n^{2} r^{2}}{4 \pi^{2}}
2 m \pi^{2} n^{2} r^{2}
4 m \pi^{2} n^{2} r^{2}
\frac{m n^{2} r^{2}}{8 \pi^{2}}

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