h. If we increase the side length of the square from 2.7 cm to 5.2 cm, the square's perimeter increases 20.80 ✔ cm. i. Determine the value of AP as s

increases from 2.7 cm to 5.2 cm. ΔΡ = 10 Preview j. As the valuess and P vary together in the relationship where P = 48, define AP in terms of As. p=4s/s k. Which of the following describes a relationship defined by the formula P = 48? (Select all that apply.) * Preview Since & and P are proportional, P varies at a constant rate of change with respect to s. Given any point (s, P) in the relationship, P is always 4 times as large as s. The point (5.2, 20.8) in the relationship conveys that 20.8= 4(5.2). For any change in s, As, away from a point (8₁, P₁) in the relationship, AP = 4As. ✔Given any two points in the relationship (81, P₁) and (82, P₂), Submit P -81 = 4. from 10.80 ✔cm to