HW02_#2 Air Vent Experimental data indicate that in a region downstream of a given louvered supply vent the velocity of the emitted air is defined by v= 0.18v/x, where v and

x are expressed in m/s and meters, respectively, and vo is the initial discharge velocity of the air. For v = 3.6 m/s, determine (a) the acceleration of the air at x = 2 m, (b) the time required for the air to flow from x=1 to x=3 m. Ans: a) a = -0.0525 b) At = 6.17 s Hints: For both (a) and (b), you'll have to do some separation of variables and either take a derivative or integral to find each answer. Recognize in (a) that time is not asked for nor included in the given velocity equation.