posted 1 years ago

The clarifier radius is 42 ft and depth is 10 ft.

What is the hydraulic loading rate (critical velocity) in each clarifier in units of ft.ft2.hr 1?

posted 1 years ago

If the cancer risk is equal to X in 1 million population, find the X.

posted 1 years ago

\text { Incoming Stream: } C=10 \mathrm{mg} / \mathrm{L}, Q=55 \mathrm{~m}^{\wedge} 3 / \mathrm{s}

\text { Sewage Outfall: } C=100 \mathrm{ppm}, Q=0.5 \mathrm{~m}^{\wedge} 3 / \mathrm{s}

\text { Lake: V=1,000 m^{ } 3}

posted 1 years ago

posted 1 years ago

H: 500 m

T= 20 °C

posted 1 years ago

o Top elevation of 5.0 feet

o Top dimensions of 150 feet by 150 feet

o Bottom elevation of 0.0 feet

o 5:1 H:V Sideslopes

a. < 100,000 cf (b) 100,000 to 200,000 cf (c) 200,000 to 300,000 cf (d) >300,000 cf

\text { Prismoidal formula }-V(c f)=0.333^{*} D Y^{*}\left[A 1+A 2+\left(A 1^{*} A 2\right)^{\wedge} 0.5\right]

DY (ft) is the distance between A1 and A2

A1 (sf) is the area at surface 1

A2 (sf) is the area at surface 2

posted 1 years ago

\text { Rectangular Weir }-\mathrm{Q}(\mathrm{cfs})=\mathrm{C}^{\star} \mathrm{L}^{*} \mathrm{H}^{\wedge} 1.5

L (ft) is the weir length/width

C = 3

H (ft) is the height of the water above the weir invert

posted 1 years ago

Circular Orifice - Q (cfs) = C*A *(2*32.2*H)^0.5%3!

C = 0.6

A (ft2) is pipe area = (3.14*Diameter^2)/4 where Diameter is in ft

where H (ft) is the height of water above the centerline of the orifice

posted 1 years ago

\text { Darcy's Law- Q (cfs) }=K^{\star} i^{\star} A

A (sf) is the area at the elevation in question

• i = dH/dL = 1%3D

K (ft/s) is the hydraulic conductivity

posted 1 years ago

\text { Stage-storage-discharge curve (cfs) }-25 / d t+0

Storage (S) is the total volume (cf) at the elevation in question

Delta time (dt) is the time step (seconds) which is given

Outflow (O) is the total outflow rate (cfs) at the elevation in quêstion