posted 10 months ago

\sqrt[4]{-16}=\text { not real }

posted 10 months ago

g(x)=m x+b \text { where }\{b, m \in R \mid m \neq \pm 1, b \neq 0\} \text { and a quadratic function of the form }

h(x)=a(x-h)^{2}+k, \text { where }\{a, h, k \in R \mid a \neq \pm 1, h \neq 0, k \neq 0\}

\text { Sketch your functions } y=g(x), y=h(x), y=g(x)+h(x), y=\frac{g(x)}{h(x)}

\text { Calculate } h(g(1)) \text { and } g(h(1)) \text { showing the full process. }

posted 10 months ago

\{a, b, c \in \mathbb{R} \mid a \neq \pm 1, b \neq 0, c \neq 0\} \text {. Calculate the average rate of change over the interval }

-2 \leq x \leq 3

Estimate the instantaneous rate of change of f(x) at x = -3, using the methods of this course

How does the instantaneous rate of change differ from part b) with the instantaneous rates of

\text { change at } f(x) \text { at } x=4 \text { and } f(x) \text { at } x=-\frac{b}{2 a} ?

posted 10 months ago

posted 10 months ago

x=\pm \sqrt{e}

x=\sqrt{e}

x=-1 \text { or } x=1

x=\frac{1}{2}

x=\pm \frac{1}{2}

posted 10 months ago

Compute: 3A– 4C

\left[\begin{array}{ccc} 6 & 9 & 15 \\ 3 & -6 & -6 \end{array}\right]

\left[\begin{array}{ccc} 20 & -44 & -16 \\ -8 & 4 & -12 \end{array}\right]

\left[\begin{array}{ccc} 26 & -35 & -1 \\ -5 & -2 & -18 \end{array}\right]

\left[\begin{array}{ccc} -26 & 35 & 1 \\ 5 & 2 & 18 \end{array}\right]

Cannot be computed.

posted 10 months ago

\frac{1}{x^{2}}

\frac{2 x}{x^{2}}

\frac{x^{2}\left(\frac{2}{x}\right)-2 x \ln x^{2}}{x^{4}}

2 x\left(1-\ln x^{2}\right)

None of the above.

posted 10 months ago

e^{x^{2}+3 x}

None of the above

\frac{e^{x+3 x}}{(2 x+3)}

e^{x^{2}+3 x}(2 x+3)

x^{2} e^{x^{2}+3 x}+3 x e^{x^{2}+3 x}

posted 10 months ago

Write down the constraints in terms of x and y.

Represent the constraints on graph paper. Show the feasible region clearly onthe graph.

Write down the cost function

How many bags of each blend should the grower buy each week to minimize the cost of meeting the nutrient requirements?

5 What is the minimum cost?

What is the minimum cost?

posted 10 months ago

\log _{p} a

\log _{a} \frac{1}{p}

-\log _{a} p

-\log _{p} a

None of the above.