Moving electric charges experience a force when they pass through a magnetic field. For an isolated charge q, the force is given by F = q(v x B), where B

is the magnetic field. The magnitude of the force is ||F|| = |g|||v x B|- If the force vector F acting on a proton with an electric charge ofC moving in a magnetic field B at some velocity vector v.q = 1.2 × 10If the magnitude of the force F acting on this proton is 5.8 x 10-17 N and19the proton is moving at the speed of 334 m/s in this magnetic field B of strength 2.3 T, find the angle 0 between the velocity vector v and the magnetic field B.