Problem 3-Laplacian The Laplacian operator is defined as 2² 2² 2² v²ƒ = (3x² âx + 3yzây + ³zzªz) ƒ = 3x² + y² + əzz f and may be thought

of as an indicator of a "source of spatial slope". This should sound familiar from Problem 2. Think what Problem 2 was evaluating: div(gradient (T)) = V. (VT) = V²T Therefore, V²T = 80 R₂ e-R³-R3-R² (2R² + 2R² +2R² - 5) 1. Plot the temperature as a 3D scalar field in one plot and the Laplacian of the temperature field as a 3D scalar field in another plot. Use a subplot to put the plots side by side.