\text { If } y=\frac{\ln x^{2}}{x^{2}}, \text { then } \frac{d y}{d x}=\ldots \frac{1}{x^{2}} \frac{2 x}{x^{2}} \frac{x^{2}\left(\frac{2}{x}\right)-2 x \ln x^{2}}{x^{4}} 2 x\left(1-\ln x^{2}\right) None of the above.

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