TutorBin Question A W24x68 shape of A992 steel is used for the simply supported beam to carry a uniformly distributed load as shown in Figure 3. (A) What is the preferred grade of steel? (B) Check if the section is compact based on AISCS Section B4. Then compute ¢Mn based on Section F2.1 of AISCS by ignoring lateral-torsional buckling. Compare this value with that tabulated in Table 3-2 of AISCM. (C) Based on ¢Mn computed above, calculate the maximum factored load, Wy, which can be supported by the beam. Then compute the corresponding total load (WyL) in kips that the beam can carry, where L = beam span. Compare this total load with that tabulated in Table 3-6 of the AISCM. (D) The factored Wu (=1.2wp +1.6w) is composed of the contribution from both service dead load (WD) including self-weight of the beam, and service live load (WL). If the ratio between WL and Wp is 3, compute the maximum service live load, WL and dead load, Wp, that can be carried by the beam. Then compute the total service load, (WD + WL)l, in kips that this beam can carry. Compare this value with that (shown in green) tabulated in Table 3-6; the values in green are for another design method called Allowable Strength Design (ASD), not Load and Resistance Factor Design (LRFD). (E) Check the shear strength of the beam based on AISCS Section G2.1(a). (F) One common practice is to camber a beam using 80% of the calculated dead load deflection and rounding down to the nearest 1/4 in. increment. Using this criterion, specify the camber for this beam. (G) Check if the beam is sufficiently stiff such that the live load deflection does not exceed L/360. WII 1 = 27 ft Figure 3