Question

You have a parallel-plate capacitor with a plate area A=115cm² and a distance d=1.24cm between the plates. A potential difference V₁-85.5V is applied to the capacitor. Then, the battery is disconnected and a dielectric slab of thickness b=0.78 cm and dielectric constant ê=2.61 is inserted in the capacitor.[&o=8.85x10-¹2 F/m]

1) Calculate the capacitance Co and the amount of charge q on each plate before the dielectric slab is inserted 2) After the plate is inserted, what is the E-field in the gaps between the plates and the dielectric (E₁)and the E-field within the dielectric slab (E₂)?

Fig: 1

Fig: 2

Fig: 3

Fig: 4