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  • Q1: 7. Study Deep foundations video #6 and take notes on your Reader. Answer the following questions: What are the two resistances that contribute to pile capacity? -. Why is fs a t? If a pile is designed to support upwards (i.e., “pullout") loading only, should one consider the end bearing resistance for design?See Answer
  • Q2: A civil engineer involved in construction requires 30,000 m' of soil with 9% fines,27% fine sand, 42% coarse sand, and 22% gravel for a building project. There are four pits nearby from which these materials can be obtained. The composition of these pits is How many cubic meters must be hauled from each pit in order to meet theengineer's need?See Answer
  • Q3: Q3. The double symmetric rectangular cross-section in Figure 3 is under compression of an axialload at the positions defined by P (at the black-filled circles). a. Calculate the area and second moment of area (moment of inertia) of the cross-section in the vertical and horizontal direction (Ixx and Iyy)(5 marks) b. Calculate the moments, Mx and My, produced about the principal axes X and Y by the eccentric load(5 marks) C. Calculate the axial stress produced because of the load d. Calculate the bending stresses produced by the moments Mx and My e. Calculate the combined direct stresses at the points (A) and (B) See Answer
  • Q4: A 5 m wide and 12 m deep braced excavation is carried out in sand, as shown in Figure P19.2, where y = 18 kN/m³ and o' = 37. The struts are placed at horizontal spacing of 2.5 m. a. Determine the strut loads. b. Determine the required section modulus of the sheet-pile section, assuming ơall =170 MN/m?. c. Determine the maximum moment for the middletwo wales. See Answer
  • Q5: Q4. The structure shown in Figure 4 is a three-pin frame. a. Determine the reactions at the supports A and B b. Sketch the bending moment diagram by calculating the moments at the seven sections A, B,C, D, E, F and G(10 marks) c. Establish the location of the section that has the maximum bending moment and write down its value on the diagram(5 marks) See Answer
  • Q6: Determine the maximum load that can be allowed on a450 mm diameter driven pile shown in Figure P12.6, allowing a factor of safety of 3. Use K = 1.5 K, and 8'in computing the shaft load. Use Meyerh of's method for computing the point load.= 0.65¢' See Answer
  • Q7: A 20 m long concrete pile is shown in Figure P12.2.Estimate the ultimate point load Q, by a.) Meyerhof's method b. Vesic's method c. Coyle and Castello's method Use m = 600 in Eq. (12.28). See Answer
  • Q8: Q2. A simply supported beam, Figure 2a, with a cross-section shown in Figure 2b, is supportinga punctual load in the middle of its span. . Determine the reactions of the beam at the supports A and B b. Determine the maximum shear force sketching the shear force diagram c. Determine the moment of inertia, I, of the section Determine the values of the maximum shear stresses in the cross-section and sketch the diagram showing the values calculated(10 marks) See Answer
  • Q9: The multi-span girder in the figure has two shear plate connections that act as hinges at C and D. The mid-span girder CD is simply supported on the cantilevered ends of the left and right girders. Determine the forces in the hinges and the reactions at supports A, B,E, and F. Given: X=9 kips/ft. The magnitude of the force in the hinge C is Cy=------kips, and the direction is ( (Click to select) The magnitude of the force in the hinge D is Dy=---kips, and the direction is(Click to select) + The magnitude of the reaction at support A is Ay=kips, and the direction is ( (Click to select) The magnitude of the reaction at support B is By= kips, and the direction is (Click to select) The magnitude of the reaction at support E is Ev=----kips, and the direction is ((Click to select), The magnitude of the reaction at support F is Fy=|| kips, and the direction is ( (Click to select)See Answer
  • Q10: Side B now rests on a horizontal surface. If a horizontal force pointed to the left is applied at the top outer corner at E, what is the maximum force that can be applied before the channel will tip? Weight remains 10 N. (Ignore slipping) (Assume the horizontal force from above is removed.) If the angle of friction for the channel is 30degrees, what is the maximum horizontal force that can be applied to the right at the midpoint of A?Where is the normal force located?See Answer
  • Q11: The 1-meter base of this cantilever beam section is a symmetric fixed support. The left extension of the section is 12 m long and the right extension is 5 m long. If the couple (reactive moment) at the fixed support is 160 Nm CW, what is the load density at the left side of the section? If the load density of at the left side of the section were reduced to 0 and the original 160 Nm couple was removed, what couple must be added at the fixed support in order to maintain equilibrium? What is the force reaction at the fixed support? (with the load density at the left side of the section at 0)See Answer
  • Q12: The magnitude of the reaction at A is A-TTkips, and the direction is The magnitude of the reaction at A is Ay= -----kips, and the direction is The magnitude of the reaction at Eis Ex=kips, and the direction is The magnitude of the reaction at E is Ey =---- kips, and the direction isSee Answer
  • Q13: Supports at E and F are symmetric. Consider the location of the horizontal reaction at F at y=0. A = 1.8 m B = 1.4 m C= .8 m D= E = F = .2 m This uneven C channel is supported by a hinge at F and a frictionless support at E. If the channel section has a weight of 10 N, what is the reaction at E and F? A horizontal force acting to the left is placed at the upper outer corner at C. The reaction at E is determined to be 1 N. What is the magnitude of the horizontal force at C and the resultant magnitude of the reaction at F?See Answer
  • Q14: a) Calculate the cracking moment Mer G b) Using the transformed area method, determine the moment of inertia of the cracked section c) Calculate the flexural stresses fe, f, and f's. A 30 ft long fixed-supported T-beam is loaded with a uniform distributed load consisting of a 1.2k/ft dead load (including weight of beam) and a 1.6 k/ft live load, as shown in the figure. Becausereverse moments occur at the ends, the T-beam is reinforced with 3 #8 and 3 #10 bars at the topand 3 #8 bars at the bottom of the section with clear distances as shown in the figure. Use normalweight concrete with f'e = 4000 psi and Ec = 3600 ksi, and Grade 60 steel (f = 60,000 psi,E = 29,000 ksi).%3D%3D%3DSee Answer
  • Q15: Determine the deadweight per linear foot of the pre stressed, reinforced concrete tee:beam whose cross section is shown' in FigureP2.1. The beam is constructed with lightweight concrete which weights 120 Ibs /ft3. The deadweight of the segment is Ib/ft. See Answer
  • Q16:Establish the loading for floor beam 81.See Answer
  • Q17: A five-story bullding plan Is shown in figure (a). Following the ASCE standard, the wind pressure along the height on the windward side has been established as shown In the figure (c). Considering the windward pressure in the east-west direction, use the tributary area concept to compute the resultant wind force at each floor level. The resultant wind force at the roof is The resultant wind force at the fifth floor is The resultant wind force at the fourth floor is The resultant wind force at the third floor is The resultant wind force at the second floor isIb.See Answer
  • Q18: The uniformly distributed live load on the floor plan in the figure given below is 55 lb/ft. Consider the live load reduction if permitted by the ASCE standard. Establish the loading for floor beam B2.See Answer
  • Q19: The uniformly distributed live load on the floor plan in the figure given below is 55 Ib/ft. Consider the live load reduction if permitted by the ASCE standard. See Answer
  • Q20: Consider the five-story building shown in the figure.The average weights of the floor and roof are 100 Ib/ft and 70 Ib/it respectively. The values of Sps and Sp1 are equal to 0.9 g and 0.4 g, respectively. Since steel moment frames are used in the north-south direction to resist the seismic forces, the value of R equals 8. Compute the seismic base shear V. Then, distribute the base shear along the height of the building. The seismic base shear Vof the building is The seismic base shear Fy on the roof is The seismic base shear Fx on the fifth floor is The seismic base shear Fy on the fourth floor is The seismic base shear Fx on the third floor is The seismic base shear Fy on the second floor isSee Answer

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