BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
Lecture Section (circle one):
Lin/Boyd (001)
Gavva (002)
Stelling/Dodani (003)
Instructions:
• Include your name and UTD ID on each page.
• For full credit, all parts of each question must be answered with your own work and explanations.
• All answers must be handwritten on this handout. No additional paper should be attached.
• This is like the problem sets but will be graded for accuracy.
• No late or electronic work will be accepted.
• A stapled paper copy must be turned in by 5 PM on Tuesday May 10, 2022, in the drop box
below on the third floor of Founders outside office 3.606.
1 BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
1. The structure of Aspirin or acetylsalicylic acid is shown below. Ionization of Aspirin can
influence the pH of the stomach.
It is absorbed into the blood through the cells lining the stomach and the small intestine. Absorption
requires passage through the plasma membrane, the rate of which is determined by the polarity of
the molecule: charged and highly polar molecules pass slowly, whereas neutral hydrophobic ones
pass rapidly. The pH of the stomach after the meal is about 1.5, and the pH of the contents of
small intestine is about 6.
a) Given that at equilibrium the pH of a 0.15 M solution of Aspirin is 2.16, what is the pKa of
Aspirin?
b) Using the pKa from (a), what is the ratio of deprotonated Aspirin (Asp-) to protonated Aspirin
(HAsp) in the stomach?
BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
c) Is more Aspirin absorbed into the bloodstream from the stomach or small intestine?
Clearly justify your answer
d) During a short distance run, the muscles produce a large amount of lactic acid
(CH3CH(OH) COOH, Ka = 1.38 X 10−4) from their glucose stores. Given this fact,
why might hyperventilation (breathing rapidly and deeply) before a run be useful?
BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
2. The following reaction has a ΔG°’ = -61.9 kJ/mol at 37 °C.
Phosphoenolpyruvate (PEP) + H2O ⇌ Pyruvate + Inorganic Phosphate (Pi)
a) Is the reaction favorable under standard biochemical conditions? Explain your
answer.
b) What is the equilibrium constant (Keq’) of this reaction at 37°C?
In cells, the direct hydrolysis of PEP rarely occurs. Rather, the hydrolysis of
PEP and the reverse hydrolysis of ATP are coupled.
c) Write out the coupled reaction and determine its ΔG°’ at 37°C. The hydrolysis
of ATP has a ΔG°’ of -30.5 kJ/mol.
BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
d) At cellular concentrations of reactants and products at 37°C, the ΔG’ is -15 kJ/mol.
If ADP and ATP are at 0.5 mM and 0.3 mM respectively, what is the ratio of
pyruvate to PEP?
e) If 10-fold more PEP is added, what will be the resulting change in ΔG’?
BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
3. Coronaviruses express a nucleocapsid protein that is needed for propagation,
transcription, and assembly of the virus. The nucleocapsid protein must be phosphorylated
by a kinase in the host cell to carry out these functions. One such kinase that has been
recently reported is glycogen synthase kinase 3 or GSK-3. The following is the 10-letter
sequence of the nucleocapsid protein that is recognized and phosphorylated by GSK-3: SSRGTSPARM.
Note: pKa N-terminus = 9.3; pKa R = 12.5; pKa T = 13; pKa S = 13; pKa C-terminus = 4.3 a)
What is the sequence of the peptide using the three-letter amino acid abbreviations? b)
Draw the chemical structure of the peptide when it is at pH 8. Assign charges and label
the peptide bonds.
c) What is the pI of the peptide? Do not use an online resource to calculate this value.
Show your work to receive credit.
BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
d) Which amino acid(s) of the peptide are most plausible to be phosphorylated?
e) Does the pI increase, decrease, or stay the same if all the possible amino acids you
stated in you answer for part (d) from the sequence are phosphorylated? Explain why.
BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
4. Glycogen synthase (GS) catalyzes the formation of a(1🡪4) glycosidic bonds in glycogen
by catalyzing the transfer of UDP-glucose to a glycogen particle where UDP is a byproduct.
It is regulated by allosteric modulators and phosphorylation coupled to hormones. Assume GS
is a K-system enzyme. Given this information, answer the following questions.
a) Do you expect the binding of the substrate UDP-glucose to favor the R or T state of the
enzyme or neither?
b) Draw a plot of the rate of GS versus UDP-glucose. Label the axes, define the half-maximal
substrate binding (K0.5) point, and mark the curve with the label UDP-glucose.
c) GSK-3 from Question 3 above phosphorylates GS, thus inhibiting the enzyme. When GS is
phosphorylated, do you expect the R or T state of the enzyme or neither to be favored?
d) On the same plot that you drew for part (b) now add a second curve indicating the effect
of phosphorylation. Define the half-maximal substrate binding (K0.5) point and mark the
curve with the label GS-P.
BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
5. Natural and artificial sweeteners.
a) Draw a Haworth projection of the following α-D-glucose, β-D-fructose, and the disaccharide
from these two monosaccharides which is called sucrose or α-D-glucopyranosyl-(1→2)-β-D
fructofuranose. Clearly indicate the carbon where the α or β notation is derived from on the
monosaccharides and the glycoside linkage in the disaccharide.
b) Sucralose or better known as Splenda is the chlorinated form of sucrose, but it is not
metabolized through glycolysis like sucrose which can be broken down into glucose and
fructose. Provide a reasonable explanation for this.
BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
6. Glycogen synthase kinase 3 beta (GSK-3β) is a serine-threonine kinase known for its
ability to regulate glycogen synthesis. In addition, it has been reported that GSK-3β plays
important roles in many intracellular pathways and numerous pathologies, such as Alzheimer’s
disease and cancer. Inhibitors have been developed to modulate GSK-3β activity and used as
therapies. The kinetics of the enzyme (GSK-3β) with and without its inhibitor is shown in
the plot below.
B
A
1/v
0
(sec/μM)
1/[S](1/μM)
a) Which line indicate the condition with inhibitor, line A or line B?
b) What is the type of this inhibitor? Explain.
c) Determine Vmax and Km for this enzyme in the inhibited state. Be sure to include the units.
BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
7. An enzyme is known to obey the Michaelis-Menten kinetics with a Kcat of 30.0 s-1.
a) At what substrate concentration would this enzyme with a Km of 0.015 M operate at one quarter
of its maximum rate?
b) Determine the fraction of Vmax that would be obtained when [S] = 2Km.
c) What is the efficiency of this enzyme?
BIOL/CHEM 3361/3161
Problem Set Final
Name:
UTD ID:
12
BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
8. Using the Table provided on the previous page:
a) Calculate the standard free energy change as a pair of electrons is transferred from succinate
to molecular oxygen in the mitochondrial respiratory chain. Please show your equations and work
for full credit.
Faraday Constant: 96485 J/V.mol; Gas Constant: 8.314 J/mol; ΔpH: 1.4; ΔΨ: 0.175
b) Based on your answer in part (a), calculate the maximum number of protons that could be
pumped out of the matrix into the IMS as these electrons are passed to oxygen. Assume 37°C.
c) At which site(s) are these protons pumped?
BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
9. Based on your knowledge of oxidative phosphorylation, answer the following questions:
a) Suppose you synthesize an ATP synthase that was devoid of the γ (gamma) subunit. How would
the catalytic sites of the β subunits of such an enzyme compare to one another? Why? What if
only the c-terminus of the γ subunit is missing?
b) Cells contain a protein called IF that binds tightly to the catalytic site of ATP synthase,
inhibiting its activity under certain circumstances. Can you think of any circumstances where
such an inhibitor might be useful within a cell?
BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
10. Knowing what you have learned about enzyme mechanisms in this course, answer the following
questions:
Acetylcholinesterase, which breaks down acetylcholine, a neurotransmitter, is a target for
potential drugs for Alzheimer’s Disease, as well as chemical warfare agents. It utilizes the
same catalytic mechanism of serine proteases that were discussed in lecture and has a pH
optimum of 7.4 at 37°C. One of its unique structural features is the deep gorge formed from
mostly aromatic amino acids, at the bottom of which lies the active site residues.
a) In the image below, identify the three missing amino acids using the three-letter amino
acid code.
b) What is the mechanism of action of these three amino acids?
BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
Alkaline proteases are hydrolytic enzymes that cleave proteins into smaller peptides and amino
acids at basic pH and elevated temperatures. Because of these properties, enzymes such as these
have been common additives to laundry detergents since the 1960s to help remove stains by
degrading the protein. This biotechnological innovation has paved way for the incorporation
of natural and engineered enzymes into a range application beyond laundry detergents that
impact our everyday lives.
Assume that alkaline protease A utilizes the same catalytic mechanism of serine proteases
that were discussed in lecture, but it operates at pH 9 or above at a temperature of 60°C
or above.
c) How do you think an enzyme could carry out this transformation at pH 9? Justify your
explanation considering the side chain pKa values in the catalytic site at pH 7.4 you
described in part a.
d) How do you think an enzyme could work at 60°C? Justify your explanation considering protein
structure and intermolecular forces and drawing comparison to an enzyme that operates at 37 °C.
BIOL/CHEM 3361/3161 Problem Set Final
Name:
UTD ID:
Score sheet (do not fill out) but include in your printout that you turn in.
Question Points received
1 /8
2 /10
3 /10
4 /8
5 /8
6 /10
7 /6
8 /9
9 /8
10 /11
Total /88
PRACTICAL TOPIC 2:
Forward genetics, reverse genetics, and reporter genes
Weeks 8-9
Practical 2 is comprised of three sections: forward genetics, reverse genetics and reporter
genes. These are pillars of approaches to understanding the function of genes and, as such,
are utilized in nearly all genetic systems to which they are applicable.
LEARNING OBJECTIVE(s) for PRAC 2
A few major goals of Practical 2 are to:
1) Understand how forward genetics screens are performed in a variety of eukaryotic
organisms and how they may be tailored to suit different life cycles.
2) Be able to interpret gene expression patterns based on transcriptional and translational
reporter gene fusions and what can be inferred about gene function.
3) Be familiar with various approaches to reverse genetics, and appreciate the strengths
and weaknesses of the different techniques.
Your report will consist of:
— answers to questions 1-8 from Part A, including applicable crossing schemes for mutagenesis
analysis in questions 1-7 and a deduced genetic pathway for question 8
— answers to questions 1-7 from Part B, including annotated drawings/photos of the
reporter gene expression patterns
— answers to questions 1-7 from Part C, including a table/graph (C1) and a diagram (C5).
Most other answers for sections B and C can be accomplished with a couple sentences
76
BACKGROUND
Forward genetic screens
With the discovery by Hermann Muller that ionizing radiation induces mutations, geneticists
realized that mutant organisms could be generated at will and systematically screened for
phenotypes of interest. Mutant phenotypes provide information on the function of the wild-type
allele and insight into biological processes. In an early example, in 1908 Archibald Garrod
connected a hereditary condition, alkaptonuria, with the lack of a specific biochemical
activity, the metabolism of benzene rings in homogentisic acid. He suggested that the wild-
type version of the gene encodes the enzyme responsible for this biochemical activity.
With the ability to generate mutations at will, geneticists began to employ systematic genetic
screens to dissect other biological processes, and the genetic bases for entire biochemical
pathways were elucidated.
The design of genetic screens to identify genes involved in specific biological processes
is limited only by the imagination of the geneticist. An example is the research by Seymour
Benzer that led to the field of behavioral genetics in the 1970s. Benzer believed mutations
could be identified that specifically affect behavioral processes, such as one you are using
now, the process of learning and memory. At the time, behavior was thought by many to be too
complex to be dissected genetically. However, Chip Quinn, a graduate student in Benzer’s lab,
built on previous ideas and designed an ingenious screen to identify learning- and memory
deficient mutants in Drosophila. Wild-type flies could be taught that a pulse of odor would
be followed by a shock; later, when the flies smelled the odor, they would take evasive action.
When Quinn and Benzer subjected a mutagenized population of Drosophila to this genetic screen,
they identified mutant strains of flies that could perceive the odor but seemed unable to
associate the odor with the stimulus; either they did not learn or could not remember.
Two mutant genes identified in the study, dunce and rutabaga, were later shown to encode
proteins involved in the production or degradation of the small signaling molecule cyclic
adenosine monophosphate (cAMP). At the time, signaling via a cAMP pathway was known to be required
for learning in the sea hare, Aplysia. Since both Drosophila mutants were defective in cAMP physiology,
other genes that encoded proteins involved in cAMP signaling and response were also investigated
for roles in learning. Ultimately, a transcription factor called creb (cAMP response element binding
protein), which activates or represses genes in response to cAMP signaling, was shown to be critical
for storing memories in flies. Remarkably, creb is widely conserved in animal species, and mouse
mutants lacking creb activity also fail to remember. A similar gene is found in our genome.
A great strength of forward genetic screens is that they are unbiased; no prior knowledge
of the molecular function of the encoded gene product is required. In a sense, by performing a
mutagenesis, the geneticist is allowing the organism to reveal how its biological processes operate.
Following a genetic screen, the number of genes and number of alleles of each gene identified are
determined by complementation tests. For genes thought to act in the same pathway, the order
in which the genes act
77
can be determined by examining the phenotypes of double mutants.
In this practical you will perform a modified version of Figure 16c.
Evaluation of genetic pathways and epistasis
Three distinct types of genetic pathways can be identified. Biosynthetic pathways are networks
of interacting genes that produce a molecule or compound as their end product. Compounds such as
pigments, amino acids, nucleotides, hormones, and so on are examples of the products of biosynthetic
pathways. Signal transduction pathways are a second type of multiple-gene pathway. These pathways
are responsible for reception of chemical signals, such as hormones, that are generated outside
a cell and initiate a response inside a cell. Signal transduction operates through the release
of a signaling molecule that is part of a sequence of steps culminating in the activation or
repression of gene expression in response to an intracellular or extracellular signal. Finally,
developmental pathways consist of genes that direct the growth, development, and differentiation
of body parts and structures. Numerous developmental pathways have been identified in
organisms, and the functions of their genes have been determined by experimental analyses of mutant phenotypes.
Analysis of double mutants in genes acting in the same pathway can allow the ordering of the genes
within the pathway. Epistatic interactions, in which an allele of one gene modifies or prevents the
expression of alleles at another gene, provide information of which of the two genes acts upstream
and which acts downstream of the other. In the case of biochemical pathways, epistasis analysis is usually
straightforward, as it is usually assumed that that the enzymes act in a linear pathway (with branched
78
or parallel pathways also possible) in which a substrate is sequentially converted through a series
of intermediates to a final product. Analysis of the intermediates present in the different
mutant alleles provides substantial information as to the order in which the genes act. Furthermore,
the proteins encoded by the genes in the pathway almost always act in a positive manner. In
contrast, in both signal transduction and developmental pathways, the proteins encoded by
the genes can act either as positive or negative regulators and there is often no way of
assaying intermediate steps in the developmental pathway.
Two approaches facilitate the ordering of genes in a developmental pathway. First, if both
recessive loss-of-function and dominant gain-of-function alleles are available for some of the
genes in the pathway, epistatic interactions between such alleles can be powerfully informative.
Epistatic analysis of developmental pathways, conducted by studying recessive and dominant
mutations of the same gene, can be used to identify a group of genes that interact to control
a particular cellular process or pathway and to establish an order-of-function map for the
genes in the pathway. The analysis of double mutants and the availability of gain-of-function
alleles can be crucial in these endeavors. Alternatively, if an assay to visualize gene
expression is available, examining the expression pattern of one gene in the mutant background
of a second gene allows conclusion to be drawn about the relative order of action of the two genes.
Reporter genes
A gene can act as a reporter if its product can be detected directly or is an enzyme that produces
a detectable product. The regulatory sequences of the gene of interest are used to drive the
expression of the reporter gene. Two types of reporter gene fusions can be constructed:
transcriptional and translational.
In a transcriptional fusion, regulatory sequences directing transcription of the gene of interest
are fused directly with the coding sequences of the reporter gene. In this case, the reporter
gene will be transcribed in the pattern directed by the regulatory sequences to which it is fused.
In translational fusion, not only the regulatory sequences but also the coding sequence of the gene
of interest are fused to the reporter gene in such a way that the reading frame for translation
is maintained between the gene of interest and the reporter gene. As a result, the reporter
protein is translationally fused with the protein of interest, and the location of the reporter
protein provides information not only on the spatial and temporal transcriptional expression
pattern but also on the subcellular location of the fusion protein. In translational fusions,
care must be taken to find out if the fusion protein is still functional, since the addition of
the reporter protein could interfere with the proper folding or activity of the protein of interest.
Need to make a 2500 words report:
TOPICS:
• Health service market and their failures
• Private health insurance market and their failures
• Analysis of spending on health services
• Applying economics on the field of health
• Production and costs in health services
• Physicians payment system
• Hospital funding system
• Need the news to be attached in separate documents
• Read all the instructions in the PDF properly
PRACTICAL TOPIC 2:
Forward genetics, reverse genetics, and reporter genes
Weeks 8-9
Practical 2 is comprised of three sections: forward genetics, reverse genetics and
reporter genes. These are pillars of approaches to understanding the function of genes
and, as such, are utilized in nearly all genetic systems to which they are applicable.
LEARNING OBJECTIVE(s) for PRAC 2
A few major goals of Practical 2 are to:
1) Understand how forward genetics screens are performed in a variety of eukaryotic
organisms and how they may be tailored to suit different life cycles.
2) Be able to interpret gene expression patterns based on transcriptional and
translational reporter gene fusions and what can be inferred about gene function.
3) Be familiar with various approaches to reverse genetics, and appreciate the strengths
and weaknesses of the different techniques.
Your report will consist of:
— answers to questions 1-8 from Part A, including applicable crossing schemes for
mutagenesis analysis in questions 1-7 and a deduced genetic pathway for question 8
— answers to questions 1-7 from Part B, including annotated drawings/photos of the
reporter gene expression patterns
— answers to questions 1-7 from Part C, including a table/graph (C1) and a diagram (C5).
Most other answers for sections B and C can be accomplished with a couple sentences
76
BACKGROUND
Forward genetic screens
With the discovery by Hermann Muller that ionizing radiation induces mutations, geneticists
realized that mutant organisms could be generated at will and systematically screened for
phenotypes of interest. Mutant phenotypes provide information on the function of
the wild-type allele and insight into biological processes. In an early example,
in 1908 Archibald Garrod connected a hereditary condition, alkaptonuria, with
the lack of a specific biochemical activity, the metabolism of benzene rings
in homogentisic acid. He suggested that the wild-type version of the gene
encodes the enzyme responsible for this biochemical activity. With the ability
to generate mutations at will, geneticists began to employ systematic genetic
screens to dissect other biological processes, and the genetic bases for entire
biochemical pathways were elucidated.
The design of genetic screens to identify genes involved in specific biologica
l processes is limited only by the imagination of the geneticist. An example
is the research by Seymour Benzer that led to the field of behavioral genetics
in the 1970s. Benzer believed mutations could be identified that specifically
affect behavioral processes, such as one you are using now, the process of learning
and memory. At the time, behavior was thought by many to be too complex to be
dissected genetically. However, Chip Quinn, a graduate student in Benzer’s lab,
built on previous ideas and designed an ingenious screen to identify learning-
and memory deficient mutants in Drosophila. Wild-type flies could be taught that a
pulse of odor would be followed by a shock; later, when the flies smelled the odor,
they would take evasive action. When Quinn and Benzer subjected a mutagenized
population of Drosophila to this genetic screen, they identified mutant strains
of flies that could perceive the odor but seemed unable to associate the odor
with the stimulus; either they did not learn or could not remember.
Two mutant genes identified in the study, dunce and rutabaga, were later shown
to encode proteins involved in the production or degradation of the small
signaling molecule cyclic adenosine monophosphate (cAMP). At the time, signaling
via a cAMP pathway was known to be required for learning in the sea hare, Aplysia.
Since both Drosophila mutants were defective in cAMP physiology, other genes that
encoded proteins involved in cAMP signaling and response were also investigated for
roles in learning. Ultimately, a transcription factor called creb (cAMP response
element binding protein), which activates or represses genes in response to cAMP
signaling, was shown to be critical for storing memories in flies. Remarkably,
creb is widely conserved in animal species, and mouse mutants lacking creb
activity also fail to remember. A similar gene is found in our genome.
A great strength of forward genetic screens is that they are unbiased; no prio
r knowledge of the molecular function of the encoded gene product is
required. In a sense, by performing a mutagenesis, the geneticist is allowing
the organism to reveal how its biological processes operate. Following a
genetic screen, the number of genes and number of alleles of each gene
identified are determined by complementation tests. For genes thought to act in
the same pathway, the order in which the genes act
77
can be determined by examining the phenotypes of double mutants.
In this practical you will perform a modified version of Figure 16c.
Evaluation of genetic pathways and epistasis
Three distinct types of genetic pathways can be identified. Biosynthetic
pathways are networks of interacting genes that produce a molecule or compound
as their end product. Compounds such as pigments, amino acids, nucleotides,
hormones, and so on are examples of the products of biosynthetic pathways.
Signal transduction pathways are a second type of multiple-gene pathway. These
pathways are responsible for reception of chemical signals, such as hormones,
that are generated outside a cell and initiate a response inside a cell. Signal
transduction operates through the release of a signaling molecule that is part
of a sequence of steps culminating in the activation or repression of gene
expression in response to an intracellular or extracellular signal. Finally,
developmental pathways consist of genes that direct the growth, development,
and differentiation of body parts and structures. Numerous developmental pathways
have been identified in organisms, and the functions of their genes have been
determined by experimental analyses of mutant phenotypes.
Analysis of double mutants in genes acting in the same pathway can allow
the ordering of the genes within the pathway. Epistatic interactions, in which
an allele of one gene modifies or prevents the expression of alleles at another
gene, provide information of which of the two genes acts upstream and which acts
downstream of the other. In the case of biochemical pathways, epistasis analysis
is usually straightforward, as it is usually assumed that that the enzymes act
in a linear pathway (with branched
78
or parallel pathways also possible) in which a substrate is sequentially
converted through a series of intermediates to a final product. Analysis of the
intermediates present in the different mutant alleles provides substantial information
as to the order in which the genes act. Furthermore, the proteins encoded by the
genes in the pathway almost always act in a positive manner. In contrast, in both
First, if both recessive loss-of-function and dominant gain-of-function alleles
are available for some of the genes in the pathway, epistatic interactions between
such alleles can be powerfully informative. Epistatic analysis of developmental
pathways, conducted by studying recessive and dominant mutations of the same gene,
can be used to identify a group of genes that interact to control a particular
cellular process or pathway and to establish an order-of-function map for the
genes in the pathway. The analysis of double mutants and the availability of
gain-of-function alleles can be crucial in these endeavors. Alternatively, if an
assay to visualize gene expression is available, examining the expression pattern
of one gene in the mutant background of a second gene allows conclusion to be
drawn about the relative order of action of the two genes.
Reporter genes
A gene can act as a reporter if its product can be detected directly or is
an enzyme that produces a detectable product. The regulatory sequences of the
gene of interest are used to drive the expression of the reporter gene. Two types
of reporter gene fusions can be constructed: transcriptional and translational.
In a transcriptional fusion, regulatory sequences directing transcription
of the gene of interest are fused directly with the coding sequences of the reporter
gene. In this case, the reporter gene will be transcribed in the pattern directed by
the regulatory sequences to which it is fused. In translational fusion, not only the
regulatory sequences but also the coding sequence of the gene of interest are fused
to the reporter gene in such a way that the reading frame for translation is maintained
between the gene of interest and the reporter gene. As a result, the reporter protein
is translationally fused with the protein of interest, and the location of the reporter
protein provides information not only on the spatial and temporal transcriptional
expression pattern but also on the subcellular location of the fusion protein.
In translational fusions, care must be taken to find out if the fusion protein
is still functional, since the addition of the reporter protein could interfere
with the proper folding or activity of the protein of interest.
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