1. Given the loading acting on the frame shown here,

lb-ft

and 23, 175 16

1 ft

a. Replace the loading by an equivalent resultant force

and couple moment system acting at point A.

b. Replace the loading by a single resultant force and

specify where the resultant force passes through the

resultant force and

c. Replace the loading by a single res

specify where the

horizontal x-al

@buffatisultant force passes through the

FR = 241 +48j lb

(MR)A= 33.095 lb-ft

* = 0.6895 ft, y = -1.379 ft

40 lb

80 lb

P

2A -3 ft-

3050 lb

4ft

3 ft

50 lb

30°