1) Mr. Steele (m=120.0kg) into the wall of his house. Determine: comes in on a wrecking ball (m=450.0kg), and imbeds himself 0.500m The average force exerted by the wall to stop Mr. Steele is 8.45x10¹N.

a) The Work done to stop Mr. Steele and the ball. (1 mark)

b) How fast Mr. Steele hit the wall (assuming he is at the lowest part of his swing, v=0). (1 mark)

c) The original height which Mr. Steele swung from. (1 mark)

d) Mr. Steele's speed when his height is 4.25m off the ground. (1 mark)

e) Now, let's consider a situation with air friction. If 4525J of energy is lost

to air friction, how far into the wall would Mr. Steele and the

ball go? (1 mark)