(1 point) After putting this Max LP in standard form and then finding an optimal tableau max z = 6 x1 + 3 x2 +4 x3 S.t. 2 x1 +

2 x2 + x3 <= 200 4 x1 + x2 + 3 x3 <= 420 x1 +3 x2 <= 91 x1 , x2 , x3 >=0 we obtain We can tell there is an alternative optimal solution because of the column corresponding to which variable? x2 (enter one of x1, x2, x3, s1, s2, s3) Using that column for the next pivot column which row number in that column would become the next pivot entry 3 If we were to carry out that next step in the simplex algorithm, the new value for z will equal 20