1 text point let fxsqrt45 x the slope of the tangent line to the graph
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(1 \text { point) Let } f(x)=\sqrt{45-x} The slope of the tangent line to the graph of f(x) at the point (9, 6) is The equation of the tangent line
to the graph of f(x) at (9, 6) is y = mx + b for m = ___________ and b =___________. Hint: the slope at x = 9 is given by m=\lim _{h \rightarrow 0} \frac{f(9+h)-f(9)}{h}