(1 \text { point) Let } f(x)=\sqrt{45-x} The slope of the tangent line to the graph of f(x) at the point (9, 6) is The equation of the tangent line

to the graph of f(x) at (9, 6) is y = mx + b for m = ___________ and b =___________. Hint: the slope at x = 9 is given by m=\lim _{h \rightarrow 0} \frac{f(9+h)-f(9)}{h}