Question

2) Calculate the number of moles of chlorine needed to form 32.0 g of iron (III) chloride. \mathrm{Fe}(\mathrm{s})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightarrow \mathrm{FeCl}_{3}(\mathrm{~s})

Fig: 1

Fig: 2

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