2- Consider the arrangement of a collector tank, pump and reservoir tank shown in Figure. Taking the pump pressure requirement equation from Section 8 iv: P_{p}=\frac{1}{2} \rho_{-} x_{2}^{2}+\rho_{-} g h_{2}-\rho_{-}

g h_{1}+f_{h}-\rho_{q} P_{p}=\rho g \cdot\left(h_{2}-h_{1}+f_{h}\right) And assuming the kinetic energy term is negligible gives us: This is the general equation for calculating the pressure requirement for a pump. Combined with two other Equation (B) which gives the power that needs to be supplied to the pump (Win): W_{\text {in }}=P_{p} \cdot Q / \gamma which gives the electrical power required (We): W_{e}=I . V it is possible to derive the pump specification for a series of different diameter delivery pipes,assuming a given volumetric flow rate. A reservoir tank is 100m uphill from a water source, the difference in height between the two is 20 m. It is proposed to use a pump to push the water up to the reservoir tank at a flow rate of 0.5 1/s. Two pipe diameters of ½" and 1" are available to link the two. What size pumps are required (in Watts) for each pipe diameter, assuming a pump efficiency of 50% and what electrical current is required assuming the smaller pump is chosen and we are stealing the electricity from a 110 V pylon ?. we have 100m of pipe and for a flow rate of 0.51/s the frictional head loss chart gives the following results for ½" and 1" dia. pipes: Taking the density of water as p= 1000 Kg/m³ and the acceleration due to gravity as g = 9.81 m/s².