2. This time we have a differential equation but where the

"RHS" is of two kinds:

y" = 0 for x< 1 and y" = 4 for x2 1, with y(0) = y'(0)

= 2.

Solve this equation two different ways: by our earlier methods

but considering it to be basically two equations with different

initial conditions; and by using the LaPlace transform.