2 this time we have a differential equation but where the rhs is of tw
2. This time we have a differential equation but where the
"RHS" is of two kinds:
y" = 0 for x< 1 and y" = 4 for x2 1, with y(0) = y'(0)
Solve this equation two different ways: by our earlier methods
but considering it to be basically two equations with different
initial conditions; and by using the LaPlace transform.
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