2. What is the straight-line distance, in meters, between the letter H at Sprague Field (Location Two), and the manhole cover near the Red Hawk Diner (Location Three)? Calculate the distance in feet, then convert to meters, given the fact that there are 2.54 cm in an inch. Use EXACTLY 2.54 cm/inch for your conversion. Show ALL your calculations.

Ans- We have Coordinates of location 2(the letter H at Sprague Field ) = 40° 51.485’ N, 74° 12.080’ W Coordinates of location 3(manhole cover near the Red Hawk Diner) = 40° 51.800’ N, 74° 11.883’ W So the right angle triangle have 3 points likely (40° 51.485’ N, 74° 12.080’ W ) , (40° 51.800’ N, 74° 11.883’ W) & (40° 51.485’ N, 74° 11.883’ W) . The length of side A (40° 51.485’ N, 74° 12.080’ W & 40° 51.485’ N, 74° 11.883’ W) = √(40° 51.485’ N - 40° 51.485’ N)2 + (74° 12.080’ W- 74° 11.883’ W)2 = √ 02 + 0.1972 = 0.197 = 0.197 ˣ 4620.5 feet = 910.23 ft The length of side B = , (40° 51.800’ N, 74° 11.883’ W & 40° 51.485’ N, 74° 11.883’ W) = √ (40° 51.800’ N - 40° 51.485’ N)2 + (74° 11.883’ W -74° 11.883’ W )2 = √ 0.3152 + 02 = 0.315= 0.315 ˣ 6072.5 feet = 1912.83 ft So the straight line distance = C= √910.232 + 1912.83 2 = √828,518.65 + 3,658,918.61 = √ 4487437.26 = 2118.35 ft = 2118.35ˣ 12 inch = 25420.2 inch = 25420.2 ˣ2.54 cm= 64567.30 cm = 64567.30/ 100 = 645.67 m ( 1m = 100cm)