3) An alternative to equation 8.35a (the Colebrook-White equation) and reading the Moody diagram is the Swamee-Jain equation. Like the Haa land equation (8.35b), it is explicit in f and does not require iteration. The Swamee- Jain equation is:1225 f=\frac{1.325}{\left(\sqrt\left[\ln \left[\left(\frac{e / D}{3.7}+\frac{5.74}{\operatorname{Re}^{0.9}}\right)\right]\right)^{2}\right.} This equation gives similar accuracy as the Haaland equation in the range of5000<Re<108 and 10-6<e/D<10-2. Plot a graph of the percent difference between fcalculated by the Haaland equation and the Swamee- Jain equation compared to the original Colebrook equation for the range of Re given above and e/D = 104. This is probably easiest done with Excel, but use the program of your choice (Matlab, etc).Also note that this will be a handy tool for doing future homework problems, so set upthe spreadsheet so it is easy to use.

Question

3) An alternative to equation 8.35a (the Colebrook-White equation) and reading the Moody diagram is the Swamee-Jain equation. Like the Haa land equation (8.35b), it is explicit in f and

does not require iteration. The Swamee- Jain equation is:1225 f=\frac{1.325}{\left(\sqrt\left[\ln \left[\left(\frac{e / D}{3.7}+\frac{5.74}{\operatorname{Re}^{0.9}}\right)\right]\right)^{2}\right.} This equation gives similar accuracy as the Haaland equation in the range of5000