answer is possible, give the possible answers. \text { a. } \quad J a(a, b, c)=\prod(1,2,5,6) \text { b. } \quad J \mathrm{~b}(a, b, c, d)=\prod(1,3,5,7,13,15) \text { c. } \quad J c(a, b, c, d)=\prod(1,3,6,9,11,12,14) \text { d. } \quad \mathrm{Jd}(a, b, c, d)=\sum(0,1,2,5,8,10,13) \text { map in 1's but circle 0's }
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