9 given the integral vint_01 int_02 2 y int_03 frac32 x 3 y z d z d x
Search for question
Question
9. Given the integral V=\int_{0}^{1} \int_{0}^{2-2 y} \int_{0}^{3-\frac{3}{2} x-3 y} z d z d x d y find an integral for V of the form: V=\iiint z d x d
y d z Your solution should include diagrams and/or explanations so that a reader can follow how you re-ordered the integration variables.