resistance of 0.2 2. At 60 Hz, its friction and windage losses are 1 MW, and its core losses are 1.5 MW. The field circuit has a de voltage of 120 V, and the maximum field current is 10 A. The current of the field circuit is adjustable over the range from 0 to 10 A.
1. Draw the open circuit characteristics [OCC] for this generator. Assume that this
characteristics is represented by the following relation:
2. Draw the short circuit characteristics [SCC] for this generator. Assume that this characteristics is represented by the following relation:
3. Draw the synchronous impedance (Xs) of this generator as a function of the armature current.
4. Draw the per phase equivalent circuit of the 3-Phase synchronous generator.
5. Draw the terminal voltage (V₁) versus the armature current (1) of this generator up to the rated load current for the following cases [One graph]:
A. Rated MVA with 0.8-PF-lagging load.
B. Rated MVA with 0.8-PF-leading load.
C. Rated MVA with unity load.
6. Draw the voltage regulation (VR) versus the armature current (1) of this generator up to the rated load current for the following cases [One graph]:
A. Rated MVA with 0.8-PF-lagging load.
B. Rated MVA with 0.8-PF-leading load.
C. Rated MVA with unity load.
7. Draw the losses of this synchronous generator as a function of the armature current (1).
8. Draw the efficiency of the synchronous generator (n) as a function of the load current (1) up to the rated current.
9. Draw the developed torque of this synchronous generator as a function of armature current (1).
10. Draw the rotor angle (8) of this synchronous generator as a function of armature current (1).
Fig: 1