A closed circuit contains a source X of emf V volts connected with three capacitors C1, C2 and C3. Assuming that these are the only capacitances in the circuit, illustrating

your answers with suitable diagrams, Using the relationship Q= CV show that: a) If C1, C2 and C3 are connected in parallel with X, then the total capacitance Cin the circuit is given by: C = C,+C,+C3 b) If C1, C2 and C3 are connected in series with X, then the total capacitance C in the circuit is given by: \frac{1}{C}=\frac{1}{C_{1}}+\frac{1}{C_{2}}+\frac{1}{C_{3}}