levels for a wave on a circle are: E=\frac{n^{2} h^{2}}{2 m C^{2}} where C is the circumference of the circle and n is an integer. The R-clectrons of benzene (CHg) can be treated as waves localised on a “circle"with a circumference that equals six times the carbon-carbon bond length. In thissimplified model, the lowest energy level (n=0) is singly degenerate, and all theother levels are doubly degenerate. Assuming a carbon-carbon bond length of 140 pm, usc the equation derived(c)in (b) to calculate the energies of the first four allowed levels for the T-clectrons of benzenc. (d) Calculate the wavelength of the lowest energy transition in the UVabsorption spectrum of the x-clectrons of benzene. (c) Compare the results from (c) and (d) with: O the measured value of 180 nm for the lowest energy transition in theUV spectrum of benzene; (i) the measured values of 9.4 eV and 12.3 eV for the ionisation potentialsfrom the occupied benzene R-orbitals. What is the most likely explanation for any discrepancies? \left[\text { Mass of an electron }=9.1 \times 10^{-31} \mathrm{~kg} ; 1 \mathrm{pm}=1 \times 10^{-12} \mathrm{~m} ; 1 \mathrm{~J}=6.24 \times 10^{18} \mathrm{eV}\right]
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