0 and f"(x) > 0; (B) f'(x) > 0 and f"(x) < 0; (C) f'(x) < 0 and f"(x) > 0; (D) f'(x) < 0 and f"(x) < 0. (c) i) Show that ii) Hence deduce that \frac{\sec ^{2} x+\operatorname{cosec}^{2} x}{\sec ^{2} x \operatorname{cosec}^{2} x}=1 \frac{\tan ^{2} x+1}{\sec ^{2} x \operatorname{cosec}^{2} x}=\sin ^{2} x
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