diode are ideal What is the voltage conversion ratio Va/V1 for this converter assuming periodic steady-state continuous conduction mode operation? [Select the one best answer from the choices givenbelow] \text { (a) } \frac{\mathrm{V}_{2}}{\mathrm{~V}_{1}}=\frac{\mathrm{N}_{1}}{\mathrm{~N}_{2}} \frac{\mathrm{D}}{1-\mathrm{D}} \text { (b) } \frac{V_{2}}{V_{2}}=\frac{N_{1}}{N_{2}} \frac{1}{1-D} \text { (c) } \frac{V_{2}}{V_{1}}=\frac{N_{1}}{N_{2}} D \text { (d) } \frac{V_{2}}{V_{1}}=\frac{N_{2}}{N_{1}} \frac{D}{1-D} \text { (e) } \frac{V_{2}}{V_{1}}=\frac{N_{2}}{N_{1}} \frac{1}{1-D} \text { (f) } \frac{V_{2}}{V_{1}}=\frac{N_{2}}{N_{2}} D \text { (g) } \frac{V_{2}}{V_{1}}=-\frac{N_{1}}{N_{3}} \frac{D}{1-D} \text { (h) } \frac{V_{2}}{V_{1}}=-\frac{N_{1}}{N_{2}} \frac{1}{1-D} \text { (1) } \frac{V_{2}}{V_{1}}=-\frac{N_{1}}{N_{2}} D \text { (i) } \frac{v_{2}}{v_{2}}=-\frac{N_{2}}{N_{1}} \frac{D}{1-D} \text { (k) } \frac{V_{2}}{V_{1}}=-\frac{N_{2}}{N_{1}} \frac{1}{1-D} \frac{V_{2}}{V_{1}}=-\frac{N_{2}}{N_{1}} D

Fig: 1

Fig: 2

Fig: 3

Fig: 4

Fig: 5

Fig: 6

Fig: 7

Fig: 8

Fig: 9

Fig: 10

Fig: 11

Fig: 12

Fig: 13

Fig: 14

Fig: 15