Question

Consider the following beam which is under the action of six forces. The axis of rotation is perpendicular to the beam and passes through the"Pivot". If the forces are: F = 130 N, F2 = 120 N, F3 =180 N, F4 = 145 N, F5 = 115 N, and F6 = 120 N; the distances are: a = 3.2 cm, b = 7.4 cm, and c =7.2 cm; and the angles are: a =20°, and 020°; • The torque of F isN.m. • The torque of F2 isN.m. • The torque of F3 isN.m. • The torque of F4 isN.m. • The torque of F5 isN.m. • The torque of F6 isN.m. • The net torque on the beam isN.m. • The beam will rotate • Suppose a wedge is placed 7.0 cm from the Pivot to the right. What minimum force must the wedge exert so that the beam does not rotate?F7 =N. • The direction of F, will be upwards.

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