horizontal surface, There is an external torque T (t)is applied on the wheel that drives the whole system. \left(I-M_{2} r^{2}\right) \ddot{x}_{2}-K r^{2} x_{2}=r \tau \bigcirc\left(I+M_{2} r^{2}\right) \ddot{x}_{2}+K r^{2} x_{2}=r \tau \left(I+M_{2} r^{2}\right) \ddot{x}_{2}-K r^{2} x_{2}=r \tau \left(I+M_{2} r^{2}\right) \ddot{x}_{2}+K r^{2} x_{2}=-r \tau
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