Question

Find the second order partial derivatives(y),(y)andf(y)at the point (2,1)for the following function:f(x,y)=x3+4x3y+2y30f(2,1)=12fn(x,)=16f(x,y)=200f.(2,1)=16fnx,)=20fx,)=120f.(2,1)=20fnx,月=12/nx,)=160f(2,1)=20fn(x,)=16f(x,y)=12

Fig: 1