for f r yz a xz a 2xyza find the value of sf de where p 0 0 0 p 1 1 1
For F(r) = yz² â¸ +xz²â¸ +2xyzâ¸, find the value of SF.de where P, =(0,0,0),
P₂ = (1,1,1) along
a) A straight path from P₁ to P₂
b) The path y=x² and z = √x from P₁ to P2
c) Repeat a) and b) by noticing that the vector field F(r) can be expressed as the
gradient of some scalar field f(r).
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