Given are the Bézier points of a cubic Bézier curvex(t) with \mathbf{b}_{0}=\left(\begin{array}{l} 0 \\ 0 \end{array}\right), \quad \mathbf{b}_{1}=\left(\begin{array}{c} 0 \\ 27 \end{array}\right), \quad \mathbf{b}_{2}=\left(\begin{array}{l} 27 \\ 27 \end{array}\right), \quad \mathbf{b}_{3}=\left(\begin{array}{c} 27 \\ 0 \end{array}\right) Use the de Casteljau algorithm to determine the value x(3) as well as all intermediate points!

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