Gold ions collide in a particle accelerator. Each ion is made by removing 77 electrons(19779 from an atom of gold Au in two stages. \text { In the first stage, ions of }{ }_{79}^{197} \mathrm{Au}^{32+} \text { are made. } \text { Calculate the number of electrons in an }{ }_{79}^{197} \mathrm{Au}^{32+} \text { ion. } \text { In the second stage, more electrons are removed to produce ions of }{ }_{79}^{197} \mathrm{Au}^{77+} \text {. } \text { Calculate the specific charge of an }{ }_{79}^{197} \mathrm{Au}^{77+} \text { ion. } \text { Collisions between the gold ions produce nuclei of antimatter helium-4 }\left(\begin{array}{l}

4 \\

2

\end{array} \mathrm{He}\right) \text {. } State the constituents of one nucleus of antimatter helium-4 Collisions between the gold ions lead to two annihilations: • a nucleus of antimatter helium with a nucleus of helium an antiproton with a proton. Both annihilations produce radiation. The kinetic energy of the annihilating particles is negligible. Compare the radiation produced as a result of the two different annihilations.