1. Alternate dimensionless analysis of equation 6:
Divide both sides of equation 6 by QC /V. Show that a dimensionless independent variable t quite
naturally arises as (+)t, as well as a new dimensionless group KV/Q. Define the dimensionless
dependent variable as done previously on the bottom of page 6. Obtain a new dimensionless ODE and
associated initial condition and solve to obtain I'(t). Then, using these alternate dimensionless
definitions, obtain C(t). Your result should be identical to either equation 14 or 15.
Fig: 1