Using the above reaction, how many moles of HCl are required to make 12.22 moles of MgCl2? \mathrm{Mg}(\mathrm{OH})_{2}(\mathrm{~s})+2 \mathrm{HCl}(\mathrm{aq})-\mathrm{m} 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{MgCl}_{2}(\mathrm{aq})