. Since the heat lost by metal is equal and opposite to heat gained by water. We observe that doubling the amount of metal will double the amount of heat

released by the metal. So, heat released by the metal will be -1.62x10° Jules and heat absorbed by the metal will be 1.62x10³ Jules. Now, if we use five times water then initial, but keep Ag constant, we observe that heat lost by metal is equal and opposite to heat gained by water. Therefore, heat released by metal will be -8.37×10² Jules and heat gained or absorbed by water will be 8.37x10? Jules.