standard reduction potentials.(i) C u^{+}(a q)+e^{-} \rightleftharpoons C u(s) C u^{2+}(a q)+2 e^{-} \rightleftharpoons C u(s) E° = 0.520 V E° = 0.340 V (ii) Given that the temperature variation of the standard reduction potentials above are given by: \text { Cu'/Cu: } \quad E^{0}=0.520+\left(831 \times 10^{-2}\right) \frac{1}{T-298}-\left(230 \times 10^{-3}\right) l n T \mathrm{Cu}^{2+} / \mathrm{Cu}: \quad E^{0}=0.340+\left(789 \times 10^{-2}\right) \frac{1}{\mathrm{~T}-298}-\left(334 \times 10^{-3}\right) \mathrm{ln} T -Calculate the value of Kdisp at 340 K. -Find the entropy associated with the disproportionation reaction at 340 K and comment on youranswer.
Fig: 1
Fig: 2
Fig: 3
Fig: 4
Fig: 5
Fig: 6
Fig: 7
Fig: 8
Fig: 9
Fig: 10
Fig: 11