5 \\ 0 & 6 \end{array}\right] . \text { Find } (2AT – 3B)T if possible.- \left[\begin{array}{cc} -1 & 5 \\ -2 & -5 \\ -3 & -6 \end{array}\right] None of the other choices. \left[\begin{array}{ccc} 3 & 6 & 3 \\ 12 & 15 & 18 \end{array}\right] Not possible, because A and B have different sizes. \left[\begin{array}{ccc} -1 & 1 & 0 \\ -4 & -5 & -6 \end{array}\right]
Fig: 1
Fig: 2
Fig: 3
Fig: 4
Fig: 5
Fig: 6
Fig: 7
Fig: 8
Fig: 9