Question

# Part 3: Force and Non-Perpendicular Torque Next, we'll look at an example where the force applied and the torque arm are not perpendicular. Remember: デ=デ×F F is the force causing

the torque デ is the vector distance of the torque arm A cross product means that we multiply the perpendicular components of the vectors to find the magnitude of the cross product. * F1 = F sin 0 "in this situation (notice the position of theta) The mass of the weights in each trial are: • Trial 1,3,5: 4.54 kg • Trial 2,4,6,8: 15.95 kg 1. For trial 1, what is the value of 0? 2. Pick a trial (make sure you remember which trial you used), then using the tools available explain the steps you will follow to find the torque (you don't need to calculate your answer yet just explain how you will find your answer). 3. Now that you have the process, follow the steps and plug in values to find the torque. Make sure to show your work. After, you can move onto the next section to check your answers.

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